CBSE Grade 10 Maths Chapter 9- Some Applications of Trignometry


Heights and Distances

  • Line of sight is the line drawn from the eye of the observer to the point on the object viewed by the observer.
  • Horizontal level is the horizontal line through the eye of the observer.

Angle of elevation

  • The angle of elevation is relevant for objects above horizontal level.
  • It is the angle formed by the line of sight with the horizontal level.

 

 How to convert the above figure into the right triangle?

Case I: Angle of Elevation is known



Draw PQ perpendicular to RQ.
Now ∠RQP = 90°
ΔRQP is a rt. Δ, where
PR = hypotenuse
RQ = opposite side (Perpendicular)
PQ = adjacent side (Base)

Angle of depression

  • The angle of depression is relevant for objects below horizontal level.
  • It is the angle formed by the line of sight with the horizontal level.
 

How to convert the above figure into the right triangle?

Case II: Angle of Depression is known

(i) Draw DC parallel to AB
(ii) Draw perpendicular AD on DC.
(iii) Now ∠BAC = ∠ACD = Interior alternate angles
ΔADC is an rt. Δ. where
AC = hypotenuse

CD = adjacent side (base)

AD = opposite side (Perpendicular)

Calculating Heights and Distances

To, calculate heights and distances, we can make use of trigonometric ratios.

Step 1: Draw a line diagram corresponding to the problem.

Step 2: Mark all known heights, distances and angles and denote unknown lengths by variables.

Step 3: Use the values of various trigonometric ratios of the angles to obtain the unknown lengths from the known lengths.

Note:
  • Choose a trigonometric ratio in such a way that it considers the known side and the side that you wish to calculate.
  • The eye is always considered at ground level unless the problem specifically gives the height of the observer.